2019-07-27 |

两个字符串是否是变位词

A
B
C
D
答案:
class Anagram:
    """
    @:param s1: The first string
    @:param s2: The second string
    @:return true or false
    """
    def Solution1(s1,s2):
        alist = list(s2)

        pos1 = 0
        stillOK = True

        while pos1 < len(s1) and stillOK:
            pos2 = 0
            found = False
            while pos2 < len(alist) and not found:
                if s1[pos1] == alist[pos2]:
                    found = True
                else:
                    pos2 = pos2 + 1

            if found:
                alist[pos2] = None
            else:
                stillOK = False

            pos1 = pos1 + 1

        return stillOK

    print(Solution1('abcd','dcba'))

    def Solution2(s1,s2):
        alist1 = list(s1)
        alist2 = list(s2)

        alist1.sort()
        alist2.sort()


        pos = 0
        matches = True

        while pos < len(s1) and matches:
            if alist1[pos] == alist2[pos]:
                pos = pos + 1
            else:
                matches = False

        return matches

    print(Solution2('abcde','edcbg'))

    def Solution3(s1,s2):
        c1 = [0]*26
        c2 = [0]*26

        for i in range(len(s1)):
            pos = ord(s1[i])-ord('a')
            c1[pos] = c1[pos] + 1

        for i in range(len(s2)):
            pos = ord(s2[i])-ord('a')
            c2[pos] = c2[pos] + 1

        j = 0
        stillOK = True
        while j < 26 and stillOK:
            if c1[j] == c2[j]:
                j = j + 1
            else:
                stillOK = False

        return stillOK

    print(Solution3('apple','pleap'))

解释:

0

剑指offer

发表评论

    评价:
    验证码: 点击我更换图片
    最新评论